A rectangular strut is 150 mm wide and 120 mm thick. It carries a load of 180 kN at an eccentricity of 10 mm in a plane bisecting the thickness as shown in the figure:

The maximum intensity of stress in the section will be

This question was previously asked in

ESE Mechanical 2019: Official Paper

Option 1 : 14 MPa

CT 1: Ratio and Proportion

2672

10 Questions
16 Marks
30 Mins

**Concept:**

In this case due to eccentricity of load, stress is induced due to the **bending moment as well as due to the axial compressive load i.e.**

Maximum Intensity of Stress = 𝜎_{bending} + 𝜎_{compressive}

\(\therefore {{\rm{\sigma }}_{{\rm{bending}}}} + {\rm{\;}}{{\rm{\sigma }}_{{\rm{compressive}}}} = \frac{{MY}}{I} + \frac{P}{A}\)

**Calculation:**

\({\sigma _{max}} = \frac{{180{\rm{\;}} \times {{10}^3} \times 10 \times 75}}{{\frac{{120 \times {{150}^3}}}{{12}}}} + \frac{{180 \times {{10}^3}}}{{12 \times 150}}\)

∴ σ_{max }= 4 + 10

**∴ ****σ _{max} = 14 MPa.**